Locate the shifted rotation axis
A region turns about the line y = 3
The teal region lies between the curve \(y = \sqrt{x}\) and the line \(y = 3\), for \(0 \le x \le 9\). The dashed line is the axis of rotation, the line that the region turns about. Every point on it has height 3, so its equation is \(y = 3\).
Press "Turn the region". The region sweeps out a solid around the dashed line, not around the x-axis.
Move the slider. The teal strip is a slice of the region, cut at one value of x and a small step in x thick. It meets the dashed line at a right angle and sweeps the teal disk centered on that line.
The axis is a horizontal or a vertical line
The region can have any shape, if one edge lies along the axis. The dashed line is horizontal, so its equation is \(y = k\), where \(k\) is the height where it crosses the y-axis. A vertical axis has an equation \(x = h\), where \(h\) is the position where it crosses the x-axis.
Move the slice. It meets the dashed line at a right angle, and the solid forms around that line, wherever the line is.
Notation
A slice meets the axis at a right angle. About a horizontal axis \(y = k\) the slices are vertical, so the variable is \(x\).
\[\cy{y = k}\ \Rightarrow\ dx\]About a vertical axis \(x = h\) the slices are horizontal for the same reason, so the variable is \(y\).
\[\cy{x = h}\ \Rightarrow\ dy\]Example 1 shows a vertical axis.
The x-axis is the line \(y = 0\), and the y-axis is the line \(x = 0\). Earlier work about a coordinate axis is the case \(k = 0\) or \(h = 0\).
The orange segment is the radius of the disk, measured from the axis to the curve, so you find the axis before you measure anything.
When it fails
A disk needs the region to touch the axis. Press the button to move the region off the line.
A gap opens between the axis and the region, so each slice sweeps a ring with a hole in its center. The second button shows the hole red: a disk formula would count it as solid, so this lesson covers regions that touch the axis.
Example 1: a vertical axis
The region between the parabola \(x = y^2\) and the line \(x = 4\) turns about the line \(x = 4\). Find the axis, the direction of the slices, the variable and its bounds.
Every point on the line \(x = 4\) has x equal to 4, so the line is vertical. It is the right edge of the region.
\[\cy{x = 4}\]A slice meets the axis at a right angle, so the slices are horizontal. Each slice is a small step \(dy\) thick, so the variable is \(y\).
\[dy\]The parabola meets the axis where \(y^2 = 4\), so y runs from \(-2\) to \(2\).
\[-2 \le y \le 2\]
Example 2: not the y-axis
The region under \(y = x^2\), for \(0 \le x \le 3\), turns about the line \(x = 3\). Find the axis, the slices and the bounds.
The line \(x = 3\) is vertical, and it touches the region along its whole right edge.
\[\cy{x = 3}\]A tempting wrong move: A vertical line is the y-axis, so the region turns about the y-axis.
\[x = 3\ \text{means the y-axis}\]The red dashed line is the y-axis, \(x = 0\), three units to the left. It touches the region only at the origin, but the line \(x = 3\) touches the whole right edge.
The axis is the line \(x = 3\). A slice meets it at a right angle, so the slices are horizontal and the variable is \(y\).
The curve reaches the axis at \(y = 3^2 = 9\), and the region begins on the x-axis, so y runs from 0 to 9.
\[0 \le y \le 9\]
Practice
The region is bounded by the y-axis, the line \(y = 6\) and the line \(y = 3x\). It turns about the line \(y = 6\). State the axis, the slices, the variable and the bounds.
Move the slider along the dashed line. The slice meets the line at a right angle.
Solution
The axis is the horizontal line \(y = 6\). A slice meets it at a right angle, so the slices are vertical and the variable is \(x\).
\[\cy{y = 6}\ \Rightarrow\ dx\]The line \(y = 3x\) meets the axis where \(3x = 6\), at \(x = 2\). The y-axis is the left end, so the bounds are 0 and 2.
\[0 \le x \le 2\]
Questions
A triangle has corners at \((1, 1)\), \((5, 1)\) and \((5, 4)\). It turns about the dashed line along its right edge.
What is the equation of the dashed line?
- \(x = 5\)
- \(y = 5\)
- \(x = 0\)
- \(y = 1\)
Answer
\(x = 5\)
Which variable and which bounds does the integral for the volume use?
- \(y\), from 1 to 4
- \(x\), from 1 to 5
- \(y\), from 0 to 4
Answer
\(y\), from 1 to 4
A region lies between the curve \(y = x^2\) and the line \(y = 9\). It turns about the line \(y = 9\). Over which values of x do the slices run?
- \(-3\) to 3
- 0 to 9
- \(-9\) to 9
Answer
\(-3\) to 3
Summary
You read the equation of the axis, \(y = k\) or \(x = h\), and place the slices at right angles to that line.
Each slice at a right angle to the axis sweeps a disk centered on that line, wherever the line is.
When a problem names a line other than a coordinate axis, find that line first, before you write a radius.
This is one of four skills in topic 8.10 of Which & Why: AP Calculus.